Base | Representation |
---|---|
bin | 11111001010100010011100… |
… | …011101001001000101000011 |
3 | 122222022011011102112212110112 |
4 | 133022202130131021011003 |
5 | 120431122244014010021 |
6 | 1203302054111221535 |
7 | 40604343210433112 |
oct | 3712423435110503 |
9 | 588264142485415 |
10 | 137063621235011 |
11 | 3a74439aa45039 |
12 | 13457a215178ab |
13 | 5b630759443b3 |
14 | 25bbcb3ba3c79 |
15 | 10ca5153a3d5b |
hex | 7ca89c749143 |
137063621235011 has 2 divisors, whose sum is σ = 137063621235012. Its totient is φ = 137063621235010.
The previous prime is 137063621234989. The next prime is 137063621235031. The reversal of 137063621235011 is 110532126360731.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-137063621235011 is a prime.
It is a Sophie Germain prime.
It is a self number, because there is not a number n which added to its sum of digits gives 137063621235011.
It is not a weakly prime, because it can be changed into another prime (137063621235031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68531810617505 + 68531810617506.
It is an arithmetic number, because the mean of its divisors is an integer number (68531810617506).
Almost surely, 2137063621235011 is an apocalyptic number.
137063621235011 is a deficient number, since it is larger than the sum of its proper divisors (1).
137063621235011 is an equidigital number, since it uses as much as digits as its factorization.
137063621235011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 136080, while the sum is 41.
Adding to 137063621235011 its reverse (110532126360731), we get a palindrome (247595747595742).
The spelling of 137063621235011 in words is "one hundred thirty-seven trillion, sixty-three billion, six hundred twenty-one million, two hundred thirty-five thousand, eleven".
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