Base | Representation |
---|---|
bin | 10011111100110111111… |
… | …001100101110100011001 |
3 | 11212001212121100211022122 |
4 | 103330313321211310121 |
5 | 134430333244131132 |
6 | 2525502114431025 |
7 | 201024314133014 |
oct | 23746771456431 |
9 | 4761777324278 |
10 | 1371032411417 |
11 | 4894a7065239 |
12 | 1a186bb92475 |
13 | 9c3983b9706 |
14 | 4a50334837b |
15 | 259e4eba912 |
hex | 13f37e65d19 |
1371032411417 has 2 divisors, whose sum is σ = 1371032411418. Its totient is φ = 1371032411416.
The previous prime is 1371032411407. The next prime is 1371032411447. The reversal of 1371032411417 is 7141142301731.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 998088913936 + 372943497481 = 999044^2 + 610691^2 .
It is a cyclic number.
It is not a de Polignac number, because 1371032411417 - 24 = 1371032411401 is a prime.
It is not a weakly prime, because it can be changed into another prime (1371032411407) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 685516205708 + 685516205709.
It is an arithmetic number, because the mean of its divisors is an integer number (685516205709).
Almost surely, 21371032411417 is an apocalyptic number.
It is an amenable number.
1371032411417 is a deficient number, since it is larger than the sum of its proper divisors (1).
1371032411417 is an equidigital number, since it uses as much as digits as its factorization.
1371032411417 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 14112, while the sum is 35.
The spelling of 1371032411417 in words is "one trillion, three hundred seventy-one billion, thirty-two million, four hundred eleven thousand, four hundred seventeen".
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