Base | Representation |
---|---|
bin | 11111001011101101011010… |
… | …110100011100001010001011 |
3 | 122222120211221211111122010221 |
4 | 133023231122310130022023 |
5 | 120433432131323043333 |
6 | 1203403050242050511 |
7 | 40613223152315344 |
oct | 3713553264341213 |
9 | 588524854448127 |
10 | 137144124424843 |
11 | 3a775550997088 |
12 | 1346b549949a37 |
13 | 5b6a8350aa173 |
14 | 25c1b4d6c50cb |
15 | 10cc677b1ad2d |
hex | 7cbb5ad1c28b |
137144124424843 has 2 divisors, whose sum is σ = 137144124424844. Its totient is φ = 137144124424842.
The previous prime is 137144124424831. The next prime is 137144124424849. The reversal of 137144124424843 is 348424421441731.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-137144124424843 is a prime.
It is not a weakly prime, because it can be changed into another prime (137144124424849) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68572062212421 + 68572062212422.
It is an arithmetic number, because the mean of its divisors is an integer number (68572062212422).
Almost surely, 2137144124424843 is an apocalyptic number.
137144124424843 is a deficient number, since it is larger than the sum of its proper divisors (1).
137144124424843 is an equidigital number, since it uses as much as digits as its factorization.
137144124424843 is an evil number, because the sum of its binary digits is even.
The product of its digits is 8257536, while the sum is 52.
The spelling of 137144124424843 in words is "one hundred thirty-seven trillion, one hundred forty-four billion, one hundred twenty-four million, four hundred twenty-four thousand, eight hundred forty-three".
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