Base | Representation |
---|---|
bin | 10011111101100001101… |
… | …000011010100110000011 |
3 | 11212010200101210122201211 |
4 | 103331201220122212003 |
5 | 134433302013131232 |
6 | 2530055405110551 |
7 | 201050545211263 |
oct | 23754150324603 |
9 | 4763611718654 |
10 | 1371732552067 |
11 | 4898262a0279 |
12 | 1a1a26558457 |
13 | 9c47a477b17 |
14 | 4a56c31b7a3 |
15 | 25a366b9a47 |
hex | 13f61a1a983 |
1371732552067 has 2 divisors, whose sum is σ = 1371732552068. Its totient is φ = 1371732552066.
The previous prime is 1371732551999. The next prime is 1371732552077. The reversal of 1371732552067 is 7602552371731.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1371732552067 - 215 = 1371732519299 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1371732552067.
It is not a weakly prime, because it can be changed into another prime (1371732552077) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 685866276033 + 685866276034.
It is an arithmetic number, because the mean of its divisors is an integer number (685866276034).
Almost surely, 21371732552067 is an apocalyptic number.
1371732552067 is a deficient number, since it is larger than the sum of its proper divisors (1).
1371732552067 is an equidigital number, since it uses as much as digits as its factorization.
1371732552067 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1852200, while the sum is 49.
The spelling of 1371732552067 in words is "one trillion, three hundred seventy-one billion, seven hundred thirty-two million, five hundred fifty-two thousand, sixty-seven".
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