Base | Representation |
---|---|
bin | 11111001100110000100001… |
… | …111001010011001101110010 |
3 | 122222211201221210000021210002 |
4 | 133030300201321103031302 |
5 | 120441122221030413100 |
6 | 1203500124501310002 |
7 | 40621353644254544 |
oct | 3714604171231562 |
9 | 588751853007702 |
10 | 137216183841650 |
11 | 3a7a3069618511 |
12 | 134814ba405302 |
13 | 5b7457a0a3534 |
14 | 25c5427a21694 |
15 | 10ce493e292d5 |
hex | 7ccc21e53372 |
137216183841650 has 12 divisors (see below), whose sum is σ = 255222101945562. Its totient is φ = 54886473536640.
The previous prime is 137216183841637. The next prime is 137216183841691. The reversal of 137216183841650 is 56148381612731.
It can be written as a sum of positive squares in 3 ways, for example, as 63599045959801 + 73617137881849 = 7974901^2 + 8580043^2 .
It is a super-2 number, since 2×1372161838416502 (a number of 29 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 1372161838367 + ... + 1372161838466.
Almost surely, 2137216183841650 is an apocalyptic number.
137216183841650 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
137216183841650 is a deficient number, since it is larger than the sum of its proper divisors (118005918103912).
137216183841650 is a wasteful number, since it uses less digits than its factorization.
137216183841650 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2744323676845 (or 2744323676840 counting only the distinct ones).
The product of its (nonzero) digits is 5806080, while the sum is 56.
The spelling of 137216183841650 in words is "one hundred thirty-seven trillion, two hundred sixteen billion, one hundred eighty-three million, eight hundred forty-one thousand, six hundred fifty".
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