Search a number
-
+
137311674000593 is a prime number
BaseRepresentation
bin11111001110001001011101…
…100011010110010011010001
3200000011212102122120222010112
4133032021131203112103101
5120444203302021004333
61204012040123011105
740631304200234441
oct3716113543262321
9600155378528115
10137311674000593
113a82a6102a1244
1213497b09969a95
135b80587472071
1425c9cc5b34121
1510d1bd227e948
hex7ce25d8d64d1

137311674000593 has 2 divisors, whose sum is σ = 137311674000594. Its totient is φ = 137311674000592.

The previous prime is 137311674000521. The next prime is 137311674000619. The reversal of 137311674000593 is 395000476113731.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 110261928322624 + 27049745677969 = 10500568^2 + 5200937^2 .

It is a cyclic number.

It is not a de Polignac number, because 137311674000593 - 28 = 137311674000337 is a prime.

It is not a weakly prime, because it can be changed into another prime (137311674009593) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68655837000296 + 68655837000297.

It is an arithmetic number, because the mean of its divisors is an integer number (68655837000297).

Almost surely, 2137311674000593 is an apocalyptic number.

It is an amenable number.

137311674000593 is a deficient number, since it is larger than the sum of its proper divisors (1).

137311674000593 is an equidigital number, since it uses as much as digits as its factorization.

137311674000593 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1428840, while the sum is 50.

The spelling of 137311674000593 in words is "one hundred thirty-seven trillion, three hundred eleven billion, six hundred seventy-four million, five hundred ninety-three", and thus it is an aban number.