Base | Representation |
---|---|
bin | 11111001110001001011101… |
… | …100011010110010011010001 |
3 | 200000011212102122120222010112 |
4 | 133032021131203112103101 |
5 | 120444203302021004333 |
6 | 1204012040123011105 |
7 | 40631304200234441 |
oct | 3716113543262321 |
9 | 600155378528115 |
10 | 137311674000593 |
11 | 3a82a6102a1244 |
12 | 13497b09969a95 |
13 | 5b80587472071 |
14 | 25c9cc5b34121 |
15 | 10d1bd227e948 |
hex | 7ce25d8d64d1 |
137311674000593 has 2 divisors, whose sum is σ = 137311674000594. Its totient is φ = 137311674000592.
The previous prime is 137311674000521. The next prime is 137311674000619. The reversal of 137311674000593 is 395000476113731.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 110261928322624 + 27049745677969 = 10500568^2 + 5200937^2 .
It is a cyclic number.
It is not a de Polignac number, because 137311674000593 - 28 = 137311674000337 is a prime.
It is not a weakly prime, because it can be changed into another prime (137311674009593) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68655837000296 + 68655837000297.
It is an arithmetic number, because the mean of its divisors is an integer number (68655837000297).
Almost surely, 2137311674000593 is an apocalyptic number.
It is an amenable number.
137311674000593 is a deficient number, since it is larger than the sum of its proper divisors (1).
137311674000593 is an equidigital number, since it uses as much as digits as its factorization.
137311674000593 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1428840, while the sum is 50.
The spelling of 137311674000593 in words is "one hundred thirty-seven trillion, three hundred eleven billion, six hundred seventy-four million, five hundred ninety-three", and thus it is an aban number.
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.082 sec. • engine limits •