Base | Representation |
---|---|
bin | 10011111110110100111… |
… | …011011011000000101011 |
3 | 11212021021210102120111101 |
4 | 103332310323123000223 |
5 | 134444132242342220 |
6 | 2530450210142231 |
7 | 201130304535163 |
oct | 23766473330053 |
9 | 4767253376441 |
10 | 1373130043435 |
11 | 48a383126217 |
12 | 1a2156581977 |
13 | 9c640b587a7 |
14 | 4a661b795a3 |
15 | 25ab921630a |
hex | 13fb4edb02b |
1373130043435 has 32 divisors (see below), whose sum is σ = 1693554115968. Its totient is φ = 1068477972480.
The previous prime is 1373130043423. The next prime is 1373130043459. The reversal of 1373130043435 is 5343400313731.
It is not a de Polignac number, because 1373130043435 - 215 = 1373130010667 is a prime.
It is a super-2 number, since 2×13731300434352 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1373130043394 and 1373130043403.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 8984619 + ... + 9136171.
It is an arithmetic number, because the mean of its divisors is an integer number (52923566124).
Almost surely, 21373130043435 is an apocalyptic number.
1373130043435 is a deficient number, since it is larger than the sum of its proper divisors (320424072533).
1373130043435 is a wasteful number, since it uses less digits than its factorization.
1373130043435 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 151975.
The product of its (nonzero) digits is 136080, while the sum is 37.
The spelling of 1373130043435 in words is "one trillion, three hundred seventy-three billion, one hundred thirty million, forty-three thousand, four hundred thirty-five".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.075 sec. • engine limits •