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137341224193 is a prime number
BaseRepresentation
bin111111111101000101…
…1001100010100000001
3111010111112202002000011
41333322023030110001
54222233323133233
6143032123024521
712631305100225
oct1777213142401
9433445662004
10137341224193
11532785a4568
122274b36b141
13cc49ab0384
14690c48a785
15388c5d10cd
hex1ffa2cc501

137341224193 has 2 divisors, whose sum is σ = 137341224194. Its totient is φ = 137341224192.

The previous prime is 137341224161. The next prime is 137341224217. The reversal of 137341224193 is 391422143731.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 124631593024 + 12709631169 = 353032^2 + 112737^2 .

It is an emirp because it is prime and its reverse (391422143731) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 137341224193 - 25 = 137341224161 is a prime.

It is a super-2 number, since 2×1373412241932 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (137348224193) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68670612096 + 68670612097.

It is an arithmetic number, because the mean of its divisors is an integer number (68670612097).

Almost surely, 2137341224193 is an apocalyptic number.

It is an amenable number.

137341224193 is a deficient number, since it is larger than the sum of its proper divisors (1).

137341224193 is an equidigital number, since it uses as much as digits as its factorization.

137341224193 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 108864, while the sum is 40.

The spelling of 137341224193 in words is "one hundred thirty-seven billion, three hundred forty-one million, two hundred twenty-four thousand, one hundred ninety-three".