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1375055455489 is a prime number
BaseRepresentation
bin10100000000100111101…
…100010010010100000001
311212110020222102122021221
4110000213230102110001
5140012103144033424
62531405230315041
7201226104344332
oct24004754222401
94773228378257
101375055455489
11490180a58851
121a25b3358a81
139c889a18c71
144a7a577a289
1525b7d2939e4
hex14027b12501

1375055455489 has 2 divisors, whose sum is σ = 1375055455490. Its totient is φ = 1375055455488.

The previous prime is 1375055455447. The next prime is 1375055455547. The reversal of 1375055455489 is 9845545505731.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 972014584464 + 403040871025 = 985908^2 + 634855^2 .

It is a cyclic number.

It is not a de Polignac number, because 1375055455489 - 215 = 1375055422721 is a prime.

It is a super-2 number, since 2×13750554554892 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1375055455429) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 687527727744 + 687527727745.

It is an arithmetic number, because the mean of its divisors is an integer number (687527727745).

Almost surely, 21375055455489 is an apocalyptic number.

It is an amenable number.

1375055455489 is a deficient number, since it is larger than the sum of its proper divisors (1).

1375055455489 is an equidigital number, since it uses as much as digits as its factorization.

1375055455489 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 75600000, while the sum is 61.

The spelling of 1375055455489 in words is "one trillion, three hundred seventy-five billion, fifty-five million, four hundred fifty-five thousand, four hundred eighty-nine".