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137508264574921 is a prime number
BaseRepresentation
bin11111010001000000100011…
…010000110111111111001001
3200000212122212101102212212001
4133101000203100313333021
5121010413411212344141
61204242231421151001
740651433661446062
oct3721004320677711
9600778771385761
10137508264574921
113a8a5a22579479
121350a0336bb461
135b95c873180a6
1425d56150b3569
1510d6d8b238a31
hex7d1023437fc9

137508264574921 has 2 divisors, whose sum is σ = 137508264574922. Its totient is φ = 137508264574920.

The previous prime is 137508264574897. The next prime is 137508264574927. The reversal of 137508264574921 is 129475462805731.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 72150822058896 + 65357442516025 = 8494164^2 + 8084395^2 .

It is a cyclic number.

It is not a de Polignac number, because 137508264574921 - 221 = 137508262477769 is a prime.

It is not a weakly prime, because it can be changed into another prime (137508264574927) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68754132287460 + 68754132287461.

It is an arithmetic number, because the mean of its divisors is an integer number (68754132287461).

It is a 1-persistent number, because it is pandigital, but 2⋅137508264574921 = 275016529149842 is not.

Almost surely, 2137508264574921 is an apocalyptic number.

It is an amenable number.

137508264574921 is a deficient number, since it is larger than the sum of its proper divisors (1).

137508264574921 is an equidigital number, since it uses as much as digits as its factorization.

137508264574921 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 101606400, while the sum is 64.

The spelling of 137508264574921 in words is "one hundred thirty-seven trillion, five hundred eight billion, two hundred sixty-four million, five hundred seventy-four thousand, nine hundred twenty-one".