Base | Representation |
---|---|
bin | 11001100111011101… |
… | …01001010111010001 |
3 | 1022111110020222222001 |
4 | 30303232221113101 |
5 | 211131202033303 |
6 | 10152401314001 |
7 | 664543412251 |
oct | 146356512721 |
9 | 38443228861 |
10 | 13752767953 |
11 | 5918096131 |
12 | 27b9935901 |
13 | 13b2328322 |
14 | 94671b961 |
15 | 55759931d |
hex | 333ba95d1 |
13752767953 has 2 divisors, whose sum is σ = 13752767954. Its totient is φ = 13752767952.
The previous prime is 13752767927. The next prime is 13752767971. The reversal of 13752767953 is 35976725731.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12680336449 + 1072431504 = 112607^2 + 32748^2 .
It is a cyclic number.
It is not a de Polignac number, because 13752767953 - 25 = 13752767921 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13752767894 and 13752767903.
It is not a weakly prime, because it can be changed into another prime (13752767923) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6876383976 + 6876383977.
It is an arithmetic number, because the mean of its divisors is an integer number (6876383977).
Almost surely, 213752767953 is an apocalyptic number.
It is an amenable number.
13752767953 is a deficient number, since it is larger than the sum of its proper divisors (1).
13752767953 is an equidigital number, since it uses as much as digits as its factorization.
13752767953 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 8334900, while the sum is 55.
The spelling of 13752767953 in words is "thirteen billion, seven hundred fifty-two million, seven hundred sixty-seven thousand, nine hundred fifty-three".
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