Base | Representation |
---|---|
bin | 10100000010010101100… |
… | …000111111101000010011 |
3 | 11212122000101111001021222 |
4 | 110002111200333220103 |
5 | 140024341341123024 |
6 | 2532312130235255 |
7 | 201322546541501 |
oct | 24022540775023 |
9 | 4778011431258 |
10 | 1376897989139 |
11 | 490a37023632 |
12 | 1a2a28425b2b |
13 | 9cac167bb6a |
14 | 4a8dc365671 |
15 | 25c39dee85e |
hex | 1409583fa13 |
1376897989139 has 2 divisors, whose sum is σ = 1376897989140. Its totient is φ = 1376897989138.
The previous prime is 1376897989067. The next prime is 1376897989153. The reversal of 1376897989139 is 9319897986731.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1376897989139 - 216 = 1376897923603 is a prime.
It is a super-3 number, since 3×13768979891393 (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (1376897989169) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 688448994569 + 688448994570.
It is an arithmetic number, because the mean of its divisors is an integer number (688448994570).
Almost surely, 21376897989139 is an apocalyptic number.
1376897989139 is a deficient number, since it is larger than the sum of its proper divisors (1).
1376897989139 is an equidigital number, since it uses as much as digits as its factorization.
1376897989139 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1111065984, while the sum is 80.
The spelling of 1376897989139 in words is "one trillion, three hundred seventy-six billion, eight hundred ninety-seven million, nine hundred eighty-nine thousand, one hundred thirty-nine".
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