Base | Representation |
---|---|
bin | 11111010011111010111000… |
… | …010111000000000000011001 |
3 | 200001120210021121021012001112 |
4 | 133103322320113000000121 |
5 | 121022203132111401213 |
6 | 1204514200245430105 |
7 | 41002045621550132 |
oct | 3723727027000031 |
9 | 601523247235045 |
10 | 137708334481433 |
11 | 3a97285a847451 |
12 | 1354096a70b335 |
13 | 5bababcc72361 |
14 | 2601194590c89 |
15 | 10dc19a8baea8 |
hex | 7d3eb85c0019 |
137708334481433 has 2 divisors, whose sum is σ = 137708334481434. Its totient is φ = 137708334481432.
The previous prime is 137708334481369. The next prime is 137708334481453. The reversal of 137708334481433 is 334184433807731.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 102314782715929 + 35393551765504 = 10115077^2 + 5949248^2 .
It is a cyclic number.
It is not a de Polignac number, because 137708334481433 - 26 = 137708334481369 is a prime.
It is not a weakly prime, because it can be changed into another prime (137708334481453) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68854167240716 + 68854167240717.
It is an arithmetic number, because the mean of its divisors is an integer number (68854167240717).
Almost surely, 2137708334481433 is an apocalyptic number.
It is an amenable number.
137708334481433 is a deficient number, since it is larger than the sum of its proper divisors (1).
137708334481433 is an equidigital number, since it uses as much as digits as its factorization.
137708334481433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48771072, while the sum is 59.
The spelling of 137708334481433 in words is "one hundred thirty-seven trillion, seven hundred eight billion, three hundred thirty-four million, four hundred eighty-one thousand, four hundred thirty-three".
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