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137708334481433 is a prime number
BaseRepresentation
bin11111010011111010111000…
…010111000000000000011001
3200001120210021121021012001112
4133103322320113000000121
5121022203132111401213
61204514200245430105
741002045621550132
oct3723727027000031
9601523247235045
10137708334481433
113a97285a847451
121354096a70b335
135bababcc72361
142601194590c89
1510dc19a8baea8
hex7d3eb85c0019

137708334481433 has 2 divisors, whose sum is σ = 137708334481434. Its totient is φ = 137708334481432.

The previous prime is 137708334481369. The next prime is 137708334481453. The reversal of 137708334481433 is 334184433807731.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 102314782715929 + 35393551765504 = 10115077^2 + 5949248^2 .

It is a cyclic number.

It is not a de Polignac number, because 137708334481433 - 26 = 137708334481369 is a prime.

It is not a weakly prime, because it can be changed into another prime (137708334481453) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 68854167240716 + 68854167240717.

It is an arithmetic number, because the mean of its divisors is an integer number (68854167240717).

Almost surely, 2137708334481433 is an apocalyptic number.

It is an amenable number.

137708334481433 is a deficient number, since it is larger than the sum of its proper divisors (1).

137708334481433 is an equidigital number, since it uses as much as digits as its factorization.

137708334481433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48771072, while the sum is 59.

The spelling of 137708334481433 in words is "one hundred thirty-seven trillion, seven hundred eight billion, three hundred thirty-four million, four hundred eighty-one thousand, four hundred thirty-three".