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13774443006793 = 71967777572399
BaseRepresentation
bin1100100001110001110011…
…0010000100101101001001
31210202211020121122111102011
43020130130302010231021
53301140024402204133
645143520341535521
72621112352503220
oct310343462045511
953684217574364
1013774443006793
114430787a841a7
1216656b51145a1
1378bc02baccb1
14358988053cb7
1518d488e316cd
hexc871cc84b49

13774443006793 has 4 divisors (see below), whose sum is σ = 15742220579200. Its totient is φ = 11806665434388.

The previous prime is 13774443006739. The next prime is 13774443006817. The reversal of 13774443006793 is 39760034447731.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13774443006793 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13774443006293) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 983888786193 + ... + 983888786206.

It is an arithmetic number, because the mean of its divisors is an integer number (3935555144800).

Almost surely, 213774443006793 is an apocalyptic number.

It is an amenable number.

13774443006793 is a deficient number, since it is larger than the sum of its proper divisors (1967777572407).

13774443006793 is an equidigital number, since it uses as much as digits as its factorization.

13774443006793 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1967777572406.

The product of its (nonzero) digits is 32006016, while the sum is 58.

The spelling of 13774443006793 in words is "thirteen trillion, seven hundred seventy-four billion, four hundred forty-three million, six thousand, seven hundred ninety-three".

Divisors: 1 7 1967777572399 13774443006793