Base | Representation |
---|---|
bin | 10100000100000110110… |
… | …110101000000011000001 |
3 | 11212210220220111001102002 |
4 | 110010012312220003001 |
5 | 140042240132010441 |
6 | 2533224534033345 |
7 | 201420636151532 |
oct | 24040666500301 |
9 | 4783826431362 |
10 | 1378799485121 |
11 | 491822400713 |
12 | 1a32791a8855 |
13 | a00355b7606 |
14 | 4aa3cadc689 |
15 | 25cebd05b9b |
hex | 14106da80c1 |
1378799485121 has 2 divisors, whose sum is σ = 1378799485122. Its totient is φ = 1378799485120.
The previous prime is 1378799485111. The next prime is 1378799485153. The reversal of 1378799485121 is 1215849978731.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1351548078721 + 27251406400 = 1162561^2 + 165080^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1378799485121 is a prime.
It is not a weakly prime, because it can be changed into another prime (1378799485111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 689399742560 + 689399742561.
It is an arithmetic number, because the mean of its divisors is an integer number (689399742561).
Almost surely, 21378799485121 is an apocalyptic number.
It is an amenable number.
1378799485121 is a deficient number, since it is larger than the sum of its proper divisors (1).
1378799485121 is an equidigital number, since it uses as much as digits as its factorization.
1378799485121 is an evil number, because the sum of its binary digits is even.
The product of its digits is 30481920, while the sum is 65.
The spelling of 1378799485121 in words is "one trillion, three hundred seventy-eight billion, seven hundred ninety-nine million, four hundred eighty-five thousand, one hundred twenty-one".
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