Base | Representation |
---|---|
bin | 10100000100100111101… |
… | …101001100111010001001 |
3 | 11212212100022121210000221 |
4 | 110010213231030322021 |
5 | 140044402232202133 |
6 | 2533355343430041 |
7 | 201440411116525 |
oct | 24044755147211 |
9 | 4785308553027 |
10 | 1379350662793 |
11 | 491a85542654 |
12 | 1a33b18b5321 |
13 | a00c284ab4c |
14 | 4aa91db6d85 |
15 | 25d303cca2d |
hex | 14127b4ce89 |
1379350662793 has 4 divisors (see below), whose sum is σ = 1379353516560. Its totient is φ = 1379347809028.
The previous prime is 1379350662737. The next prime is 1379350662797. The reversal of 1379350662793 is 3972660539731.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1379350662793 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1379350662797) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 502063 + ... + 1735156.
It is an arithmetic number, because the mean of its divisors is an integer number (344838379140).
Almost surely, 21379350662793 is an apocalyptic number.
It is an amenable number.
1379350662793 is a deficient number, since it is larger than the sum of its proper divisors (2853767).
1379350662793 is an equidigital number, since it uses as much as digits as its factorization.
1379350662793 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2853766.
The product of its (nonzero) digits is 38578680, while the sum is 61.
The spelling of 1379350662793 in words is "one trillion, three hundred seventy-nine billion, three hundred fifty million, six hundred sixty-two thousand, seven hundred ninety-three".
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