Base | Representation |
---|---|
bin | 10100000100110001001… |
… | …100110010100100110001 |
3 | 11212212202102022211012111 |
4 | 110010301030302210301 |
5 | 140100214021012411 |
6 | 2533423233325321 |
7 | 201444354001243 |
oct | 24046114624461 |
9 | 4785672284174 |
10 | 1379509938481 |
11 | 49205743a854 |
12 | 1a3437106841 |
13 | a0119846a0c |
14 | 4aaa91d8093 |
15 | 25d3e390721 |
hex | 14131332931 |
1379509938481 has 2 divisors, whose sum is σ = 1379509938482. Its totient is φ = 1379509938480.
The previous prime is 1379509938461. The next prime is 1379509938533. The reversal of 1379509938481 is 1848399059731.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1080310784400 + 299199154081 = 1039380^2 + 546991^2 .
It is a cyclic number.
It is not a de Polignac number, because 1379509938481 - 221 = 1379507841329 is a prime.
It is a super-2 number, since 2×13795099384812 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1379509938421) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 689754969240 + 689754969241.
It is an arithmetic number, because the mean of its divisors is an integer number (689754969241).
Almost surely, 21379509938481 is an apocalyptic number.
It is an amenable number.
1379509938481 is a deficient number, since it is larger than the sum of its proper divisors (1).
1379509938481 is an equidigital number, since it uses as much as digits as its factorization.
1379509938481 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 58786560, while the sum is 67.
The spelling of 1379509938481 in words is "one trillion, three hundred seventy-nine billion, five hundred nine million, nine hundred thirty-eight thousand, four hundred eighty-one".
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