Base | Representation |
---|---|
bin | 10000011100110… |
… | …11101000111001 |
3 | 100121200011201102 |
4 | 20032123220321 |
5 | 240312012303 |
6 | 21405501145 |
7 | 3263663066 |
oct | 1016335071 |
9 | 317604642 |
10 | 138000953 |
11 | 70997182 |
12 | 3a2717b5 |
13 | 2278a48c |
14 | 14483c6d |
15 | c1ae288 |
hex | 839ba39 |
138000953 has 2 divisors, whose sum is σ = 138000954. Its totient is φ = 138000952.
The previous prime is 138000931. The next prime is 138000979. The reversal of 138000953 is 359000831.
138000953 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 127418944 + 10582009 = 11288^2 + 3253^2 .
It is a cyclic number.
It is not a de Polignac number, because 138000953 - 214 = 137984569 is a prime.
It is a Chen prime.
It is equal to p7805540 and since 138000953 and 7805540 have the same sum of digits, it is a Honaker prime.
It is not a weakly prime, because it can be changed into another prime (138000053) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 69000476 + 69000477.
It is an arithmetic number, because the mean of its divisors is an integer number (69000477).
Almost surely, 2138000953 is an apocalyptic number.
It is an amenable number.
138000953 is a deficient number, since it is larger than the sum of its proper divisors (1).
138000953 is an equidigital number, since it uses as much as digits as its factorization.
138000953 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3240, while the sum is 29.
The square root of 138000953 is about 11747.3806867744. The cubic root of 138000953 is about 516.7661147915.
The spelling of 138000953 in words is "one hundred thirty-eight million, nine hundred fifty-three", and thus it is an aban number.
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