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138034129 is a prime number
BaseRepresentation
bin10000011101000…
…11101111010001
3100121201212020011
420032203233101
5240314043004
621410314521
73264161602
oct1016435721
9317655204
10138034129
1170a0a0a2
123a288a41
132279c5cc
1414491da9
15c1b9004
hex83a3bd1

138034129 has 2 divisors, whose sum is σ = 138034130. Its totient is φ = 138034128.

The previous prime is 138034123. The next prime is 138034147. The reversal of 138034129 is 921430831.

138034129 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 135769104 + 2265025 = 11652^2 + 1505^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-138034129 is a prime.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 138034129.

It is not a weakly prime, because it can be changed into another prime (138034123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 69017064 + 69017065.

It is an arithmetic number, because the mean of its divisors is an integer number (69017065).

Almost surely, 2138034129 is an apocalyptic number.

It is an amenable number.

138034129 is a deficient number, since it is larger than the sum of its proper divisors (1).

138034129 is an equidigital number, since it uses as much as digits as its factorization.

138034129 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5184, while the sum is 31.

The square root of 138034129 is about 11748.7926613759. The cubic root of 138034129 is about 516.8075223775.

The spelling of 138034129 in words is "one hundred thirty-eight million, thirty-four thousand, one hundred twenty-nine".