Base | Representation |
---|---|
bin | 101001001010101… |
… | …1010001100000001 |
3 | 10120021020112201221 |
4 | 1102111122030001 |
5 | 10312111002001 |
6 | 345022555041 |
7 | 46142141662 |
oct | 12225321401 |
9 | 3507215657 |
10 | 1381344001 |
11 | 649807214 |
12 | 326738a81 |
13 | 19024901b |
14 | d1657369 |
15 | 8140c1a1 |
hex | 5255a301 |
1381344001 has 2 divisors, whose sum is σ = 1381344002. Its totient is φ = 1381344000.
The previous prime is 1381343987. The next prime is 1381344031. The reversal of 1381344001 is 1004431831.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1088934001 + 292410000 = 32999^2 + 17100^2 .
It is a cyclic number.
It is not a de Polignac number, because 1381344001 - 25 = 1381343969 is a prime.
It is a super-2 number, since 2×13813440012 = 3816222498197376002, which contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1381344031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 690672000 + 690672001.
It is an arithmetic number, because the mean of its divisors is an integer number (690672001).
Almost surely, 21381344001 is an apocalyptic number.
It is an amenable number.
1381344001 is a deficient number, since it is larger than the sum of its proper divisors (1).
1381344001 is an equidigital number, since it uses as much as digits as its factorization.
1381344001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1152, while the sum is 25.
The square root of 1381344001 is about 37166.4364850869. The cubic root of 1381344001 is about 1113.6975954278.
Adding to 1381344001 its reverse (1004431831), we get a palindrome (2385775832).
The spelling of 1381344001 in words is "one billion, three hundred eighty-one million, three hundred forty-four thousand, one".
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