13817650483753 has 2 divisors, whose sum is σ = 13817650483754. Its totient is φ = 13817650483752.

The previous prime is 13817650483717. The next prime is 13817650483781. The reversal of 13817650483753 is 35738405671831.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12454949130649 + 1362701353104 = 3529157^2 + 1167348^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13817650483753 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13817650483691 and 13817650483700.

It is not a weakly prime, because it can be changed into another prime (13817650483253) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6908825241876 + 6908825241877.

It is an arithmetic number, because the mean of its divisors is an integer number (6908825241877).

Almost surely, 2^{13817650483753} is an apocalyptic number.

It is an amenable number.

13817650483753 is a deficient number, since it is larger than the sum of its proper divisors (1).

13817650483753 is an equidigital number, since it uses as much as digits as its factorization.

13817650483753 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 50803200, while the sum is 61.

The spelling of 13817650483753 in words is "thirteen trillion, eight hundred seventeen billion, six hundred fifty million, four hundred eighty-three thousand, seven hundred fifty-three".