Base | Representation |
---|---|
bin | 10100000111011011011… |
… | …000001011010111010011 |
3 | 11220011010101201112100112 |
4 | 110013123120023113103 |
5 | 140122040423102243 |
6 | 2535014424311535 |
7 | 201605203024415 |
oct | 24073330132723 |
9 | 4804111645315 |
10 | 1382365050323 |
11 | 49329203a614 |
12 | 1a3ab33125ab |
13 | a04831cbcca |
14 | 4ac9a4869b5 |
15 | 25e59d64818 |
hex | 141db60b5d3 |
1382365050323 has 2 divisors, whose sum is σ = 1382365050324. Its totient is φ = 1382365050322.
The previous prime is 1382365050307. The next prime is 1382365050329. The reversal of 1382365050323 is 3230505632831.
It is a strong prime.
It is an emirp because it is prime and its reverse (3230505632831) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1382365050323 - 24 = 1382365050307 is a prime.
It is not a weakly prime, because it can be changed into another prime (1382365050329) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 691182525161 + 691182525162.
It is an arithmetic number, because the mean of its divisors is an integer number (691182525162).
Almost surely, 21382365050323 is an apocalyptic number.
1382365050323 is a deficient number, since it is larger than the sum of its proper divisors (1).
1382365050323 is an equidigital number, since it uses as much as digits as its factorization.
1382365050323 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 388800, while the sum is 41.
The spelling of 1382365050323 in words is "one trillion, three hundred eighty-two billion, three hundred sixty-five million, fifty thousand, three hundred twenty-three".
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