Search a number
-
+
1383177781057 is a prime number
BaseRepresentation
bin10100001000001011110…
…100011111111101000001
311220020020001000112022211
4110020023310133331001
5140130222002443212
62535231220102121
7201634302102652
oct24101364377501
94806201015284
101383177781057
11493669886206
121a409b534941
13a05826bb677
144ad363a7529
1525ea63a39a7
hex1420bd1ff41

1383177781057 has 2 divisors, whose sum is σ = 1383177781058. Its totient is φ = 1383177781056.

The previous prime is 1383177780991. The next prime is 1383177781067. The reversal of 1383177781057 is 7501877713831.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1295490134416 + 87687646641 = 1138196^2 + 296121^2 .

It is a cyclic number.

It is not a de Polignac number, because 1383177781057 - 215 = 1383177748289 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1383177780992 and 1383177781010.

It is not a weakly prime, because it can be changed into another prime (1383177781067) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 691588890528 + 691588890529.

It is an arithmetic number, because the mean of its divisors is an integer number (691588890529).

Almost surely, 21383177781057 is an apocalyptic number.

It is an amenable number.

1383177781057 is a deficient number, since it is larger than the sum of its proper divisors (1).

1383177781057 is an equidigital number, since it uses as much as digits as its factorization.

1383177781057 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6914880, while the sum is 58.

The spelling of 1383177781057 in words is "one trillion, three hundred eighty-three billion, one hundred seventy-seven million, seven hundred eighty-one thousand, fifty-seven".