13833952639457 has 4 divisors (see below), whose sum is σ = 13833961132080. Its totient is φ = 13833944146836.

The previous prime is 13833952639393. The next prime is 13833952639469. The reversal of 13833952639457 is 75493625933831.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 13833952639457 - 2⁶ = 13833952639393 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13833952639957) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 949907 + ... + 5345112.

It is an arithmetic number, because the mean of its divisors is an integer number (3458490283020).

Almost surely, 2^{13833952639457} is an apocalyptic number.

It is an amenable number.

13833952639457 is a deficient number, since it is larger than the sum of its proper divisors (8492623).

13833952639457 is an equidigital number, since it uses as much as digits as its factorization.

13833952639457 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8492622.

The product of its digits is 440899200, while the sum is 68.

The spelling of 13833952639457 in words is "thirteen trillion, eight hundred thirty-three billion, nine hundred fifty-two million, six hundred thirty-nine thousand, four hundred fifty-seven".