Base | Representation |
---|---|
bin | 1100100111000010100110… |
… | …1111011000000110000011 |
3 | 1211002110121120020020111101 |
4 | 3021300221233120012003 |
5 | 3304130210301414203 |
6 | 45253232030355231 |
7 | 2630463011402416 |
oct | 311605157300603 |
9 | 54073546206441 |
10 | 13864854716803 |
11 | 44660630390a2 |
12 | 167b12795bb17 |
13 | 7975b10b385c |
14 | 35d0c38c3b7d |
15 | 1909cb4d641d |
hex | c9c29bd8183 |
13864854716803 has 2 divisors, whose sum is σ = 13864854716804. Its totient is φ = 13864854716802.
The previous prime is 13864854716771. The next prime is 13864854716813. The reversal of 13864854716803 is 30861745846831.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13864854716803 - 25 = 13864854716771 is a prime.
It is not a weakly prime, because it can be changed into another prime (13864854716813) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6932427358401 + 6932427358402.
It is an arithmetic number, because the mean of its divisors is an integer number (6932427358402).
Almost surely, 213864854716803 is an apocalyptic number.
13864854716803 is a deficient number, since it is larger than the sum of its proper divisors (1).
13864854716803 is an equidigital number, since it uses as much as digits as its factorization.
13864854716803 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 92897280, while the sum is 64.
The spelling of 13864854716803 in words is "thirteen trillion, eight hundred sixty-four billion, eight hundred fifty-four million, seven hundred sixteen thousand, eight hundred three".
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