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1387438601057 = 11692311866259
BaseRepresentation
bin10100001100001001110…
…010001111001101100001
311220122012222111121112222
4110030021302033031201
5140212433240213212
62541214104200425
7202145010344465
oct24141162171541
94818188447488
101387438601057
11495455a13353
121a4a8a469115
13a0ab1370632
144b21c2124a5
1526155498c72
hex14309c8f361

1387438601057 has 4 divisors (see below), whose sum is σ = 1387450584240. Its totient is φ = 1387426617876.

The previous prime is 1387438601047. The next prime is 1387438601093. The reversal of 1387438601057 is 7501068347831.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1387438601057 - 232 = 1383143633761 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1387438601027) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5816207 + ... + 6050052.

It is an arithmetic number, because the mean of its divisors is an integer number (346862646060).

Almost surely, 21387438601057 is an apocalyptic number.

It is an amenable number.

1387438601057 is a deficient number, since it is larger than the sum of its proper divisors (11983183).

1387438601057 is a wasteful number, since it uses less digits than its factorization.

1387438601057 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11983182.

The product of its (nonzero) digits is 3386880, while the sum is 53.

The spelling of 1387438601057 in words is "one trillion, three hundred eighty-seven billion, four hundred thirty-eight million, six hundred one thousand, fifty-seven".

Divisors: 1 116923 11866259 1387438601057