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13874741041 = 71982105863
BaseRepresentation
bin11001110101111111…
…11011111100110001
31022210221202212120211
430322333323330301
5211403413203131
610212435504121
71000554232030
oct147277737461
938727685524
1013874741041
11597aa25337
122832758041
131401693355
149589cc717
1556313e5b1
hex33affbf31

13874741041 has 4 divisors (see below), whose sum is σ = 15856846912. Its totient is φ = 11892635172.

The previous prime is 13874741033. The next prime is 13874741087. The reversal of 13874741041 is 14014747831.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13874741041 - 23 = 13874741033 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13874740985 and 13874741003.

It is not an unprimeable number, because it can be changed into a prime (13874741141) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 991052925 + ... + 991052938.

It is an arithmetic number, because the mean of its divisors is an integer number (3964211728).

Almost surely, 213874741041 is an apocalyptic number.

It is an amenable number.

13874741041 is a deficient number, since it is larger than the sum of its proper divisors (1982105871).

13874741041 is an equidigital number, since it uses as much as digits as its factorization.

13874741041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1982105870.

The product of its (nonzero) digits is 75264, while the sum is 40.

The spelling of 13874741041 in words is "thirteen billion, eight hundred seventy-four million, seven hundred forty-one thousand, forty-one".

Divisors: 1 7 1982105863 13874741041