Base | Representation |
---|---|
bin | 11001110111001001… |
… | …11011101100111001 |
3 | 1022211122000121011120 |
4 | 30323210323230321 |
5 | 211413404024403 |
6 | 10213423415453 |
7 | 1001032534011 |
oct | 147344735471 |
9 | 38748017146 |
10 | 13884439353 |
11 | 5985449874 |
12 | 2835a54589 |
13 | 14036aa7b5 |
14 | 959dd4c41 |
15 | 563e07e53 |
hex | 33b93bb39 |
13884439353 has 4 divisors (see below), whose sum is σ = 18512585808. Its totient is φ = 9256292900.
The previous prime is 13884439339. The next prime is 13884439357. The reversal of 13884439353 is 35393448831.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 13884439353 - 225 = 13850884921 is a prime.
It is a super-2 number, since 2×138844393532 (a number of 21 digits) contains 22 as substring.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 13884439296 and 13884439305.
It is not an unprimeable number, because it can be changed into a prime (13884439357) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2314073223 + ... + 2314073228.
It is an arithmetic number, because the mean of its divisors is an integer number (4628146452).
Almost surely, 213884439353 is an apocalyptic number.
It is an amenable number.
13884439353 is a deficient number, since it is larger than the sum of its proper divisors (4628146455).
13884439353 is an equidigital number, since it uses as much as digits as its factorization.
13884439353 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4628146454.
The product of its digits is 3732480, while the sum is 51.
The spelling of 13884439353 in words is "thirteen billion, eight hundred eighty-four million, four hundred thirty-nine thousand, three hundred fifty-three".
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