Search a number
-
+
138940051 is a prime number
BaseRepresentation
bin10000100100000…
…00111010010011
3100200102212220211
420102000322103
5241032040201
621441544551
73304654015
oct1022007223
9320385824
10138940051
1171478798
123a645157
1322a28a63
141464a1b5
15c2e7651
hex8480e93

138940051 has 2 divisors, whose sum is σ = 138940052. Its totient is φ = 138940050.

The previous prime is 138940019. The next prime is 138940093. The reversal of 138940051 is 150049831.

It is a weak prime.

It is an emirp because it is prime and its reverse (150049831) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 138940051 - 25 = 138940019 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 138939995 and 138940022.

It is not a weakly prime, because it can be changed into another prime (138920051) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 69470025 + 69470026.

It is an arithmetic number, because the mean of its divisors is an integer number (69470026).

Almost surely, 2138940051 is an apocalyptic number.

138940051 is a deficient number, since it is larger than the sum of its proper divisors (1).

138940051 is an equidigital number, since it uses as much as digits as its factorization.

138940051 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4320, while the sum is 31.

The square root of 138940051 is about 11787.2834444583. The cubic root of 138940051 is about 517.9356655491.

Adding to 138940051 its reverse (150049831), we get a palindrome (288989882).

The spelling of 138940051 in words is "one hundred thirty-eight million, nine hundred forty thousand, fifty-one".