Base | Representation |
---|---|
bin | 11001111000010011… |
… | …00111001111110001 |
3 | 1022212022010010012211 |
4 | 30330021213033301 |
5 | 211423334224042 |
6 | 10214405452121 |
7 | 1001210342452 |
oct | 147411471761 |
9 | 38768103184 |
10 | 13894054897 |
11 | 598a9170a8 |
12 | 2839111041 |
13 | 1405696378 |
14 | 95b3b9129 |
15 | 564ba7017 |
hex | 33c2673f1 |
13894054897 has 2 divisors, whose sum is σ = 13894054898. Its totient is φ = 13894054896.
The previous prime is 13894054891. The next prime is 13894054939. The reversal of 13894054897 is 79845049831.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12552737521 + 1341317376 = 112039^2 + 36624^2 .
It is a cyclic number.
It is not a de Polignac number, because 13894054897 - 211 = 13894052849 is a prime.
It is a super-2 number, since 2×138940548972 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13894054891) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6947027448 + 6947027449.
It is an arithmetic number, because the mean of its divisors is an integer number (6947027449).
Almost surely, 213894054897 is an apocalyptic number.
It is an amenable number.
13894054897 is a deficient number, since it is larger than the sum of its proper divisors (1).
13894054897 is an equidigital number, since it uses as much as digits as its factorization.
13894054897 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 8709120, while the sum is 58.
The spelling of 13894054897 in words is "thirteen billion, eight hundred ninety-four million, fifty-four thousand, eight hundred ninety-seven".
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