Base | Representation |
---|---|
bin | 10100001110001101000… |
… | …110000010000101100001 |
3 | 11220211220111211211111010 |
4 | 110032031012002011201 |
5 | 140231441222333343 |
6 | 2542220442211133 |
7 | 202253420516052 |
oct | 24161506020541 |
9 | 4824814754433 |
10 | 1389641605473 |
11 | 496386505160 |
12 | 1a53a41b3aa9 |
13 | a10728b4644 |
14 | 4b38aa32729 |
15 | 26233aaad33 |
hex | 1438d182161 |
1389641605473 has 32 divisors (see below), whose sum is σ = 2185185853440. Its totient is φ = 776316000960.
The previous prime is 1389641605441. The next prime is 1389641605523. The reversal of 1389641605473 is 3745061469831.
It is not a de Polignac number, because 1389641605473 - 25 = 1389641605441 is a prime.
It is a super-2 number, since 2×13896416054732 (a number of 25 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (57).
It is not an unprimeable number, because it can be changed into a prime (1389641604473) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 29927265 + ... + 29973662.
It is an arithmetic number, because the mean of its divisors is an integer number (68287057920).
Almost surely, 21389641605473 is an apocalyptic number.
It is an amenable number.
1389641605473 is a deficient number, since it is larger than the sum of its proper divisors (795544247967).
1389641605473 is a wasteful number, since it uses less digits than its factorization.
1389641605473 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 59900997.
The product of its (nonzero) digits is 13063680, while the sum is 57.
The spelling of 1389641605473 in words is "one trillion, three hundred eighty-nine billion, six hundred forty-one million, six hundred five thousand, four hundred seventy-three".
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