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13900359353 = 43323264171
BaseRepresentation
bin11001111001000011…
…01010011010111001
31022212201222102022012
430330201222122321
5211431442444403
610215152535305
71001315051006
oct147441523271
938781872265
1013900359353
1159934327a1
12283b251535
131406a92b0a
1495c17a8ad
155654eeed8
hex33c86a6b9

13900359353 has 4 divisors (see below), whose sum is σ = 14223623568. Its totient is φ = 13577095140.

The previous prime is 13900359331. The next prime is 13900359377. The reversal of 13900359353 is 35395300931.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13900359353 - 26 = 13900359289 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13900359353.

It is not an unprimeable number, because it can be changed into a prime (13902359353) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 161632043 + ... + 161632128.

It is an arithmetic number, because the mean of its divisors is an integer number (3555905892).

Almost surely, 213900359353 is an apocalyptic number.

It is an amenable number.

13900359353 is a deficient number, since it is larger than the sum of its proper divisors (323264215).

13900359353 is an equidigital number, since it uses as much as digits as its factorization.

13900359353 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 323264214.

The product of its (nonzero) digits is 164025, while the sum is 41.

The spelling of 13900359353 in words is "thirteen billion, nine hundred million, three hundred fifty-nine thousand, three hundred fifty-three".

Divisors: 1 43 323264171 13900359353