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1390244518657 is a prime number
BaseRepresentation
bin10100001110110001000…
…001111101101100000001
311220220110112022222220001
4110032301001331230001
5140234210044044112
62542400340520001
7202304361300331
oct24166101755401
94826415288801
101390244518657
11496665872815
121a55320b0001
13a113a7901c7
144b406b370c1
152626b9a1c57
hex143b107db01

1390244518657 has 2 divisors, whose sum is σ = 1390244518658. Its totient is φ = 1390244518656.

The previous prime is 1390244518639. The next prime is 1390244518667. The reversal of 1390244518657 is 7568154420931.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1356551713521 + 33692805136 = 1164711^2 + 183556^2 .

It is a cyclic number.

It is not a de Polignac number, because 1390244518657 - 231 = 1388097035009 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1390244518598 and 1390244518607.

It is not a weakly prime, because it can be changed into another prime (1390244518667) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 695122259328 + 695122259329.

It is an arithmetic number, because the mean of its divisors is an integer number (695122259329).

It is a 1-persistent number, because it is pandigital, but 2⋅1390244518657 = 2780489037314 is not.

Almost surely, 21390244518657 is an apocalyptic number.

It is an amenable number.

1390244518657 is a deficient number, since it is larger than the sum of its proper divisors (1).

1390244518657 is an equidigital number, since it uses as much as digits as its factorization.

1390244518657 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 7257600, while the sum is 55.

The spelling of 1390244518657 in words is "one trillion, three hundred ninety billion, two hundred forty-four million, five hundred eighteen thousand, six hundred fifty-seven".