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1390649753 is a prime number
BaseRepresentation
bin101001011100011…
…1010000110011001
310120220202022211102
41102320322012121
510322001243003
6345554241145
746314220313
oct12270720631
93526668742
101390649753
11653a92819
123298861b5
1319215689c
14d299a7b3
1582149588
hex52e3a199

1390649753 has 2 divisors, whose sum is σ = 1390649754. Its totient is φ = 1390649752.

The previous prime is 1390649723. The next prime is 1390649761. The reversal of 1390649753 is 3579460931.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 888755344 + 501894409 = 29812^2 + 22403^2 .

It is a cyclic number.

It is not a de Polignac number, because 1390649753 - 210 = 1390648729 is a prime.

It is a super-2 number, since 2×13906497532 = 3867813471037922018, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1390649698 and 1390649707.

It is not a weakly prime, because it can be changed into another prime (1390649723) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 695324876 + 695324877.

It is an arithmetic number, because the mean of its divisors is an integer number (695324877).

Almost surely, 21390649753 is an apocalyptic number.

It is an amenable number.

1390649753 is a deficient number, since it is larger than the sum of its proper divisors (1).

1390649753 is an equidigital number, since it uses as much as digits as its factorization.

1390649753 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 612360, while the sum is 47.

The square root of 1390649753 is about 37291.4166129419. The cubic root of 1390649753 is about 1116.1928965286.

The spelling of 1390649753 in words is "one billion, three hundred ninety million, six hundred forty-nine thousand, seven hundred fifty-three".