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13914439653131 = 16678346994393
BaseRepresentation
bin1100101001111011010100…
…1110111001011100001011
31211021012121020000222210122
43022132311032321130023
53310433233022400011
645332112203533455
72634166533404123
oct312366516713413
954235536028718
1013914439653131
114485098487716
12168886582a28b
1379c183b69674
1436166904bc83
15191e2e6de3db
hexca7b53b970b

13914439653131 has 4 divisors (see below), whose sum is σ = 13922786649192. Its totient is φ = 13906092657072.

The previous prime is 13914439653067. The next prime is 13914439653151. The reversal of 13914439653131 is 13135693441931.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13914439653131 - 26 = 13914439653067 is a prime.

It is a super-2 number, since 2×139144396531312 (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13914439653151) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4173495530 + ... + 4173498863.

It is an arithmetic number, because the mean of its divisors is an integer number (3480696662298).

Almost surely, 213914439653131 is an apocalyptic number.

13914439653131 is a deficient number, since it is larger than the sum of its proper divisors (8346996061).

13914439653131 is an equidigital number, since it uses as much as digits as its factorization.

13914439653131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8346996060.

The product of its digits is 3149280, while the sum is 53.

The spelling of 13914439653131 in words is "thirteen trillion, nine hundred fourteen billion, four hundred thirty-nine million, six hundred fifty-three thousand, one hundred thirty-one".

Divisors: 1 1667 8346994393 13914439653131