Base | Representation |
---|---|
bin | 1100101010101010010001… |
… | …1101000001101110001011 |
3 | 1211022102010120112200221121 |
4 | 3022222210131001232023 |
5 | 3311140041004440113 |
6 | 45341554550220111 |
7 | 2635124052441433 |
oct | 312524435015613 |
9 | 54272116480847 |
10 | 13927043046283 |
11 | 448a4757a4514 |
12 | 168b1a2654637 |
13 | 7a0412017353 |
14 | 362102c572c3 |
15 | 19241adece8d |
hex | caaa4741b8b |
13927043046283 has 2 divisors, whose sum is σ = 13927043046284. Its totient is φ = 13927043046282.
The previous prime is 13927043046271. The next prime is 13927043046347. The reversal of 13927043046283 is 38264034072931.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13927043046283 - 25 = 13927043046251 is a prime.
It is a super-3 number, since 3×139270430462833 (a number of 40 digits) contains 333 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 13927043046283.
It is not a weakly prime, because it can be changed into another prime (13927043046253) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6963521523141 + 6963521523142.
It is an arithmetic number, because the mean of its divisors is an integer number (6963521523142).
Almost surely, 213927043046283 is an apocalyptic number.
13927043046283 is a deficient number, since it is larger than the sum of its proper divisors (1).
13927043046283 is an equidigital number, since it uses as much as digits as its factorization.
13927043046283 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5225472, while the sum is 52.
The spelling of 13927043046283 in words is "thirteen trillion, nine hundred twenty-seven billion, forty-three million, forty-six thousand, two hundred eighty-three".
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