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1393041724881 = 31606728900681
BaseRepresentation
bin10100010001010111110…
…000011101010111010001
311221011200110202210110120
4110101113300131113101
5140310422140144011
62543542102420453
7202433605201452
oct24212760352721
94834613683416
101393041724881
114978708121a4
121a5b92a31729
13a149514c911
144b5d0431129
1526382338a06
hex14457c1d5d1

1393041724881 has 8 divisors (see below), whose sum is σ = 1857504633504. Its totient is φ = 928636649760.

The previous prime is 1393041724871. The next prime is 1393041724897. The reversal of 1393041724881 is 1884271403931.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 1393041724881 - 25 = 1393041724849 is a prime.

It is a super-2 number, since 2×13930417248812 (a number of 25 digits) contains 22 as substring.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (1393041724831) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 14402140 + ... + 14498541.

It is an arithmetic number, because the mean of its divisors is an integer number (232188079188).

Almost surely, 21393041724881 is an apocalyptic number.

It is an amenable number.

1393041724881 is a deficient number, since it is larger than the sum of its proper divisors (464462908623).

1393041724881 is a wasteful number, since it uses less digits than its factorization.

1393041724881 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 28916751.

The product of its (nonzero) digits is 1161216, while the sum is 51.

The spelling of 1393041724881 in words is "one trillion, three hundred ninety-three billion, forty-one million, seven hundred twenty-four thousand, eight hundred eighty-one".

Divisors: 1 3 16067 48201 28900681 86702043 464347241627 1393041724881