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139355580672 = 28327113125339
BaseRepresentation
bin1000000111001000111…
…1010110100100000000
3111022200221002222121200
42001302033112210000
54240400012040142
6144004041421200
713032234614520
oct2016217264400
9438627088550
10139355580672
1154111657390
1223011a9a800
13101ab213199
146a5dc01680
15395937c64c
hex20723d6900

139355580672 has 432 divisors, whose sum is σ = 517120880640. Its totient is φ = 35027251200.

The previous prime is 139355580671. The next prime is 139355580701. The reversal of 139355580672 is 276085553931.

139355580672 is a `hidden beast` number, since 1 + 3 + 9 + 3 + 55 + 580 + 6 + 7 + 2 = 666.

It is not an unprimeable number, because it can be changed into a prime (139355580671) by changing a digit.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 5486979 + ... + 5512317.

Almost surely, 2139355580672 is an apocalyptic number.

139355580672 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 139355580672, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (258560440320).

139355580672 is an abundant number, since it is smaller than the sum of its proper divisors (377765299968).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

139355580672 is a wasteful number, since it uses less digits than its factorization.

139355580672 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 25410 (or 25393 counting only the distinct ones).

The product of its (nonzero) digits is 6804000, while the sum is 54.

It can be divided in two parts, 139355 and 580672, that added together give a palindrome (720027).

The spelling of 139355580672 in words is "one hundred thirty-nine billion, three hundred fifty-five million, five hundred eighty thousand, six hundred seventy-two".