Base | Representation |
---|---|
bin | 1100101011111000011110… |
… | …0010110000000010101011 |
3 | 1211101102022101112220100002 |
4 | 3022332013202300002223 |
5 | 3312011032402001242 |
6 | 45355345434333215 |
7 | 2636466153665006 |
oct | 312760742600253 |
9 | 54342271486302 |
10 | 13948032843947 |
11 | 4498366a09134 |
12 | 169327bb8a20b |
13 | 7a23a8799477 |
14 | 36313479253d |
15 | 192c489d2432 |
hex | caf878b00ab |
13948032843947 has 2 divisors, whose sum is σ = 13948032843948. Its totient is φ = 13948032843946.
The previous prime is 13948032843937. The next prime is 13948032843967. The reversal of 13948032843947 is 74934823084931.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13948032843947 - 24 = 13948032843931 is a prime.
It is not a weakly prime, because it can be changed into another prime (13948032843917) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6974016421973 + 6974016421974.
It is an arithmetic number, because the mean of its divisors is an integer number (6974016421974).
Almost surely, 213948032843947 is an apocalyptic number.
13948032843947 is a deficient number, since it is larger than the sum of its proper divisors (1).
13948032843947 is an equidigital number, since it uses as much as digits as its factorization.
13948032843947 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 125411328, while the sum is 65.
The spelling of 13948032843947 in words is "thirteen trillion, nine hundred forty-eight billion, thirty-two million, eight hundred forty-three thousand, nine hundred forty-seven".
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