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139514463641 = 719930637663
BaseRepresentation
bin1000000111101110110…
…1011100010110011001
3111100010000002002002002
42001323231130112121
54241211200314031
6144031515050345
713036204242260
oct2017355342631
9440100062062
10139514463641
1154193306523
12230571409b5
1310205102387
146a76d5d5d7
1539682b3ccb
hex207bb5c599

139514463641 has 4 divisors (see below), whose sum is σ = 159445101312. Its totient is φ = 119583825972.

The previous prime is 139514463637. The next prime is 139514463667. The reversal of 139514463641 is 146364415931.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 146364415931 = 167039876229.

It is a cyclic number.

It is not a de Polignac number, because 139514463641 - 22 = 139514463637 is a prime.

It is not an unprimeable number, because it can be changed into a prime (139514463611) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9965318825 + ... + 9965318838.

It is an arithmetic number, because the mean of its divisors is an integer number (39861275328).

Almost surely, 2139514463641 is an apocalyptic number.

It is an amenable number.

139514463641 is a deficient number, since it is larger than the sum of its proper divisors (19930637671).

139514463641 is an equidigital number, since it uses as much as digits as its factorization.

139514463641 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 19930637670.

The product of its digits is 933120, while the sum is 47.

The spelling of 139514463641 in words is "one hundred thirty-nine billion, five hundred fourteen million, four hundred sixty-three thousand, six hundred forty-one".

Divisors: 1 7 19930637663 139514463641