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13960925107 = 34574038451
BaseRepresentation
bin11010000000010001…
…01100111110110011
31100000221221110220021
431000020230332303
5212042444100412
610225155024311
71002651622363
oct150010547663
940027843807
1013960925107
115a1463a738
12285759b097
1314164aa43c
149662249a3
1556a9b5607
hex34022cfb3

13960925107 has 4 divisors (see below), whose sum is σ = 13964967016. Its totient is φ = 13956883200.

The previous prime is 13960925087. The next prime is 13960925213. The reversal of 13960925107 is 70152906931.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 70152906931 = 604271160953.

It is a cyclic number.

It is not a de Polignac number, because 13960925107 - 211 = 13960923059 is a prime.

It is a super-2 number, since 2×139609251072 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13960925707) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2015769 + ... + 2022682.

It is an arithmetic number, because the mean of its divisors is an integer number (3491241754).

Almost surely, 213960925107 is an apocalyptic number.

13960925107 is a deficient number, since it is larger than the sum of its proper divisors (4041909).

13960925107 is an equidigital number, since it uses as much as digits as its factorization.

13960925107 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4041908.

The product of its (nonzero) digits is 102060, while the sum is 43.

The spelling of 13960925107 in words is "thirteen billion, nine hundred sixty million, nine hundred twenty-five thousand, one hundred seven".

Divisors: 1 3457 4038451 13960925107