Base | Representation |
---|---|
bin | 10100010100010010010… |
… | …110100110100000010011 |
3 | 11221110202122110202221121 |
4 | 110110102112212200103 |
5 | 140333330101122341 |
6 | 2545220453303111 |
7 | 202604310422641 |
oct | 24242226464023 |
9 | 4843678422847 |
10 | 1396172285971 |
11 | 499127948071 |
12 | 1a6707334a97 |
13 | a18738b8128 |
14 | 4b80a102191 |
15 | 264b70bc4d1 |
hex | 145125a6813 |
1396172285971 has 2 divisors, whose sum is σ = 1396172285972. Its totient is φ = 1396172285970.
The previous prime is 1396172285951. The next prime is 1396172286007. The reversal of 1396172285971 is 1795822716931.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1396172285971 - 211 = 1396172283923 is a prime.
It is a super-2 number, since 2×13961722859712 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1396172285951) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 698086142985 + 698086142986.
It is an arithmetic number, because the mean of its divisors is an integer number (698086142986).
Almost surely, 21396172285971 is an apocalyptic number.
1396172285971 is a deficient number, since it is larger than the sum of its proper divisors (1).
1396172285971 is an equidigital number, since it uses as much as digits as its factorization.
1396172285971 is an evil number, because the sum of its binary digits is even.
The product of its digits is 11430720, while the sum is 61.
The spelling of 1396172285971 in words is "one trillion, three hundred ninety-six billion, one hundred seventy-two million, two hundred eighty-five thousand, nine hundred seventy-one".
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