Base | Representation |
---|---|
bin | 10100010100100110000… |
… | …000101000000011000001 |
3 | 11221111121122000111211012 |
4 | 110110212000220003001 |
5 | 140340014012210231 |
6 | 2545313313530305 |
7 | 202615423506533 |
oct | 24244600500301 |
9 | 4844548014735 |
10 | 1396502069441 |
11 | 499287014296 |
12 | 1a6799873995 |
13 | a18c701348b |
14 | 4b83bc29853 |
15 | 264d6010e2b |
hex | 145260280c1 |
1396502069441 has 2 divisors, whose sum is σ = 1396502069442. Its totient is φ = 1396502069440.
The previous prime is 1396502069437. The next prime is 1396502069497. The reversal of 1396502069441 is 1449602056931.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1344428655025 + 52073414416 = 1159495^2 + 228196^2 .
It is a cyclic number.
It is not a de Polignac number, because 1396502069441 - 22 = 1396502069437 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1396502069441.
It is not a weakly prime, because it can be changed into another prime (1396502060441) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 698251034720 + 698251034721.
It is an arithmetic number, because the mean of its divisors is an integer number (698251034721).
Almost surely, 21396502069441 is an apocalyptic number.
It is an amenable number.
1396502069441 is a deficient number, since it is larger than the sum of its proper divisors (1).
1396502069441 is an equidigital number, since it uses as much as digits as its factorization.
1396502069441 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1399680, while the sum is 50.
The spelling of 1396502069441 in words is "one trillion, three hundred ninety-six billion, five hundred two million, sixty-nine thousand, four hundred forty-one".
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