Base | Representation |
---|---|
bin | 10100010100100111111… |
… | …011111101101100101001 |
3 | 11221111200212212011112012 |
4 | 110110213323331230221 |
5 | 140340100301324313 |
6 | 2545320430525305 |
7 | 202616265361214 |
oct | 24244773755451 |
9 | 4844625764465 |
10 | 1396534401833 |
11 | 4992a329807a |
12 | 1a67a8666835 |
13 | a1900923c7c |
14 | 4b84224477b |
15 | 264d8c9ada8 |
hex | 14527efdb29 |
1396534401833 has 2 divisors, whose sum is σ = 1396534401834. Its totient is φ = 1396534401832.
The previous prime is 1396534401793. The next prime is 1396534401877. The reversal of 1396534401833 is 3381044356931.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1096550348569 + 299984053264 = 1047163^2 + 547708^2 .
It is a cyclic number.
It is not a de Polignac number, because 1396534401833 - 228 = 1396265966377 is a prime.
It is a super-2 number, since 2×13965344018332 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1396534401233) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 698267200916 + 698267200917.
It is an arithmetic number, because the mean of its divisors is an integer number (698267200917).
Almost surely, 21396534401833 is an apocalyptic number.
It is an amenable number.
1396534401833 is a deficient number, since it is larger than the sum of its proper divisors (1).
1396534401833 is an equidigital number, since it uses as much as digits as its factorization.
1396534401833 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2799360, while the sum is 50.
The spelling of 1396534401833 in words is "one trillion, three hundred ninety-six billion, five hundred thirty-four million, four hundred one thousand, eight hundred thirty-three".
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