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13968000113 is a prime number
BaseRepresentation
bin11010000001000111…
…01100010001110001
31100001110020220222112
431000203230101301
5212101302000423
610230010415105
71003066020254
oct150043542161
940043226875
1013968000113
115a18632251
122859a31495
131417ab6832
1496714709b
1556b411a78
hex3408ec471

13968000113 has 2 divisors, whose sum is σ = 13968000114. Its totient is φ = 13968000112.

The previous prime is 13968000107. The next prime is 13968000121. The reversal of 13968000113 is 31100086931.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8867612224 + 5100387889 = 94168^2 + 71417^2 .

It is a cyclic number.

It is not a de Polignac number, because 13968000113 - 216 = 13967934577 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 13968000113.

It is not a weakly prime, because it can be changed into another prime (13968003113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6984000056 + 6984000057.

It is an arithmetic number, because the mean of its divisors is an integer number (6984000057).

Almost surely, 213968000113 is an apocalyptic number.

It is an amenable number.

13968000113 is a deficient number, since it is larger than the sum of its proper divisors (1).

13968000113 is an equidigital number, since it uses as much as digits as its factorization.

13968000113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3888, while the sum is 32.

The spelling of 13968000113 in words is "thirteen billion, nine hundred sixty-eight million, one hundred thirteen", and thus it is an aban number.