Base | Representation |
---|---|
bin | 1000001000100011000… |
… | …0000000101101000001 |
3 | 111100200020202002200221 |
4 | 2002020300000231001 |
5 | 4242133202200031 |
6 | 144105332143041 |
7 | 13044501643141 |
oct | 2021060005501 |
9 | 440606662627 |
10 | 139733240641 |
11 | 54295853965 |
12 | 230b8467a81 |
13 | 1023b532217 |
14 | 6a9802c921 |
15 | 397c5cba11 |
hex | 2088c00b41 |
139733240641 has 4 divisors (see below), whose sum is σ = 139735144384. Its totient is φ = 139731336900.
The previous prime is 139733240617. The next prime is 139733240657. The reversal of 139733240641 is 146042337931.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-139733240641 is a prime.
It is a super-2 number, since 2×1397332406412 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (139733240671) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 837165 + ... + 990106.
It is an arithmetic number, because the mean of its divisors is an integer number (34933786096).
Almost surely, 2139733240641 is an apocalyptic number.
It is an amenable number.
139733240641 is a deficient number, since it is larger than the sum of its proper divisors (1903743).
139733240641 is an equidigital number, since it uses as much as digits as its factorization.
139733240641 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1903742.
The product of its (nonzero) digits is 326592, while the sum is 43.
The spelling of 139733240641 in words is "one hundred thirty-nine billion, seven hundred thirty-three million, two hundred forty thousand, six hundred forty-one".
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