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13986000033 = 34662000011
BaseRepresentation
bin11010000011010000…
…10110110010100001
31100002201010102020020
431001220112302201
5212120404000113
610231452304053
71003405016205
oct150150266241
940081112206
1013986000033
115a27806915
122863a72029
13141b749785
149696b0b05
1556ccba023
hex341a16ca1

13986000033 has 4 divisors (see below), whose sum is σ = 18648000048. Its totient is φ = 9324000020.

The previous prime is 13986000019. The next prime is 13986000059. The reversal of 13986000033 is 33000068931.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13986000033 - 213 = 13985991841 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13985999958 and 13986000003.

It is not an unprimeable number, because it can be changed into a prime (13986007033) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2331000003 + ... + 2331000008.

It is an arithmetic number, because the mean of its divisors is an integer number (4662000012).

Almost surely, 213986000033 is an apocalyptic number.

It is an amenable number.

13986000033 is a deficient number, since it is larger than the sum of its proper divisors (4662000015).

13986000033 is an equidigital number, since it uses as much as digits as its factorization.

13986000033 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4662000014.

The product of its (nonzero) digits is 11664, while the sum is 33.

Adding to 13986000033 its reverse (33000068931), we get a palindrome (46986068964).

The spelling of 13986000033 in words is "thirteen billion, nine hundred eighty-six million, thirty-three", and thus it is an aban number.

Divisors: 1 3 4662000011 13986000033