Base | Representation |
---|---|
bin | 10100010110101111010… |
… | …100111001111011011001 |
3 | 11221201120012000102001021 |
4 | 110112233110321323121 |
5 | 140404223300123103 |
6 | 2550334052122441 |
7 | 203026466444305 |
oct | 24265724717331 |
9 | 4851505012037 |
10 | 1398805864153 |
11 | 49a259497365 |
12 | 1a7121306421 |
13 | a1ba33b6909 |
14 | 4b9b9ba4d05 |
15 | 265bd3d1bbd |
hex | 145af539ed9 |
1398805864153 has 2 divisors, whose sum is σ = 1398805864154. Its totient is φ = 1398805864152.
The previous prime is 1398805864123. The next prime is 1398805864177. The reversal of 1398805864153 is 3514685088931.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1346405160409 + 52400703744 = 1160347^2 + 228912^2 .
It is an emirp because it is prime and its reverse (3514685088931) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1398805864153 - 217 = 1398805733081 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1398805864091 and 1398805864100.
It is not a weakly prime, because it can be changed into another prime (1398805864123) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 699402932076 + 699402932077.
It is an arithmetic number, because the mean of its divisors is an integer number (699402932077).
Almost surely, 21398805864153 is an apocalyptic number.
It is an amenable number.
1398805864153 is a deficient number, since it is larger than the sum of its proper divisors (1).
1398805864153 is an equidigital number, since it uses as much as digits as its factorization.
1398805864153 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24883200, while the sum is 61.
The spelling of 1398805864153 in words is "one trillion, three hundred ninety-eight billion, eight hundred five million, eight hundred sixty-four thousand, one hundred fifty-three".
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