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13990433 is a prime number
BaseRepresentation
bin110101010111…
…101000100001
3222022210021012
4311113220201
512040143213
61215510305
7226626302
oct65275041
928283235
1013990433
117996246
124828395
132b8ac82
141c027a9
1513654a8
hexd57a21

13990433 has 2 divisors, whose sum is σ = 13990434. Its totient is φ = 13990432.

The previous prime is 13990409. The next prime is 13990451. The reversal of 13990433 is 33409931.

13990433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13667809 + 322624 = 3697^2 + 568^2 .

It is an emirp because it is prime and its reverse (33409931) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13990433 - 26 = 13990369 is a prime.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 13990433.

It is not a weakly prime, because it can be changed into another prime (13993433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6995216 + 6995217.

It is an arithmetic number, because the mean of its divisors is an integer number (6995217).

Almost surely, 213990433 is an apocalyptic number.

It is an amenable number.

13990433 is a deficient number, since it is larger than the sum of its proper divisors (1).

13990433 is an equidigital number, since it uses as much as digits as its factorization.

13990433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8748, while the sum is 32.

The square root of 13990433 is about 3740.3787241401. The cubic root of 13990433 is about 240.9593143097.

The spelling of 13990433 in words is "thirteen million, nine hundred ninety thousand, four hundred thirty-three".