Base | Representation |
---|---|
bin | 11010000011110011… |
… | …01101100010010001 |
3 | 1100010000200120010112 |
4 | 31001321231202101 |
5 | 212123040042044 |
6 | 10232134011105 |
7 | 1003461465326 |
oct | 150171554221 |
9 | 40100616115 |
10 | 13990549649 |
11 | 5a2a33402a |
12 | 28654a6a95 |
13 | 141c68055b |
14 | 96a136b4d |
15 | 56d3b809e |
hex | 341e6d891 |
13990549649 has 2 divisors, whose sum is σ = 13990549650. Its totient is φ = 13990549648.
The previous prime is 13990549633. The next prime is 13990549669. The reversal of 13990549649 is 94694509931.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 8522982400 + 5467567249 = 92320^2 + 73943^2 .
It is a cyclic number.
It is not a de Polignac number, because 13990549649 - 24 = 13990549633 is a prime.
It is a super-2 number, since 2×139905496492 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13990549669) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6995274824 + 6995274825.
It is an arithmetic number, because the mean of its divisors is an integer number (6995274825).
Almost surely, 213990549649 is an apocalyptic number.
It is an amenable number.
13990549649 is a deficient number, since it is larger than the sum of its proper divisors (1).
13990549649 is an equidigital number, since it uses as much as digits as its factorization.
13990549649 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9447840, while the sum is 59.
The spelling of 13990549649 in words is "thirteen billion, nine hundred ninety million, five hundred forty-nine thousand, six hundred forty-nine".
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